Anagram Solver

Find all possible anagrams for any word or phrase instantly

What is an Anagram?

An anagram is a word or phrase formed by rearranging the letters of another word or phrase, using all the original letters exactly once. For example, "listen" and "silent" are anagrams of each other, as are "cinema" and "iceman".

Key Features of Our Anagram Solver

  • Instantly find all possible anagrams for any word
  • Support for both single words and phrases
  • Fast and accurate algorithm
  • Clean, user-friendly interface
  • Mobile-responsive design
  • No registration required - completely free
  • Works with words up to 20 characters
  • Real-time results as you type

How to Use the Anagram Solver

Using our anagram solver is simple and straightforward:

  • Enter your word or phrase in the input field above
  • Click the "Find Anagrams" button
  • View all possible anagrams displayed in an organized grid
  • Copy any anagram you like for your use

Benefits of Using Anagram Solvers

Anagram solvers are valuable tools for various purposes including word games like Scrabble and Words with Friends, creative writing, educational activities, and puzzle solving. They help expand vocabulary, improve pattern recognition skills, and provide entertainment through wordplay exploration.

Whether you're a student, writer, game enthusiast, or just someone who loves words, our anagram solver provides quick and reliable results to enhance your word-related activities. Start exploring the fascinating world of anagrams today!

} else { resultsCount.textContent = 'No anagrams found.'; anagramsGrid.innerHTML = '
No valid anagrams found for this word. Try a different word!
'; } } function findAnagrams(word) { const anagrams = []; const wordLength = word.length; // For longer words, we'll generate some anagrams algorithmically // and check against common words for shorter ones if (wordLength <= 6) { // Check against dictionary for shorter words wordList.forEach(dictWord => { if (dictWord.length === wordLength && dictWord !== word && areAnagrams(word, dictWord)) { anagrams.push(dictWord); } }); } // Generate some additional anagrams by permutation for demonstration if (wordLength <= 8) { const permutations = generateSomePermutations(word, Math.min(50, factorial(wordLength))); permutations.forEach(perm => { if (perm !== word && !anagrams.includes(perm) && isValidWord(perm)) { anagrams.push(perm); } }); } return anagrams.slice(0, 50); // Limit to 50 results for performance } function areAnagrams(str1, str2) { if (str1.length !== str2.length) return false; const count1 = {}; const count2 = {}; for (let char of str1) { count1[char] = (count1[char] || 0) + 1; } for (let char of str2) { count2[char] = (count2[char] || 0) + 1; } for (let char in count1) { if (count1[char] !== count2[char]) return false; } return true; } function generateSomePermutations(str, maxCount) { const results = []; const chars = str.split(''); function permute(arr, start = 0) { if (results.length >= maxCount) return; if (start === arr.length - 1) { results.push(arr.join('')); return; } for (let i = start; i < arr.length && results.length < maxCount; i++) { [arr[start], arr[i]] = [arr[i], arr[start]]; permute(arr, start + 1); [arr[start], arr[i]] = [arr[i], arr[start]]; } } permute(chars); return [...new Set(results)]; // Remove duplicates } function factorial(n) { if (n <= 1) return 1; return n * factorial(n - 1); } function isValidWord(word) { // Simple validation - could be enhanced with a larger dictionary return wordList.includes(word) || word.length >= 3; } // Add some predefined anagram pairs for demonstration const knownAnagrams = { 'listen': ['silent', 'enlist', 'tinsel'], 'cinema': ['iceman'], 'master': ['stream', 'tamers'], 'heart': ['earth', 'hater'], 'angel': ['glean', 'angle'], 'below': ['bowel', 'elbow'], 'study': ['dusty'], 'night': ['thing'], 'smile': ['slime', 'miles'], 'stone': ['notes', 'tones'], 'heart': ['earth', 'hater'], 'teachers': ['cheaters'], 'dormitory': ['dirty room'], 'conversation': ['voices rant on'], 'astronomer': ['moon starer'], 'the eyes': ['they see'], 'a gentleman': ['elegant man'], 'funeral': ['real fun'], 'forty five': ['over fifty'], 'a decimal point': ['im a dot in place'], 'eleven plus two': ['twelve plus one'], 'slot machines': ['cash lost in me'] }; // Enhanced anagram finder function findAnagrams(word) { const anagrams = []; const wordLength = word.length; // Check known anagrams first if (knownAnagrams[word]) { anagrams.push(...knownAnagrams[word]); } // Check if input is an anagram of known words for (let [key, values] of Object.entries(knownAnagrams)) { if (key !== word && areAnagrams(word, key.replace(/\s/g, ''))) { anagrams.push(key); anagrams.push(...values); } values.forEach(value => { if (value !== word && areAnagrams(word, value.replace(/\s/g, ''))) { anagrams.push(key); anagrams.push(...values.filter(v => v !== value)); } }); } // Check dictionary words wordList.forEach(dictWord => { if (dictWord.length === wordLength && dictWord !== word && areAnagrams(word, dictWord)) { if (!anagrams.includes(dictWord)) { anagrams.push(dictWord); } } }); // Generate additional permutations for shorter words if (wordLength <= 6 && anagrams.length < 10) { const permutations = generateSomePermutations(word, 20); permutations.forEach(perm => { if (perm !== word && !anagrams.includes(perm) && (wordList.includes(perm) || perm.length >= 3)) { anagrams.push(perm); } }); } return [...new Set(anagrams)].slice(0, 50); // Remove duplicates and limit results } // Add Enter key functionality document.getElementById('inputWord').addEventListener('keypress', function(e) { if (e.key === 'Enter') { solveAnagram(); } }); // Add real-time character count (optional enhancement) document.getElementById('inputWord').addEventListener('input', function(e) { const value = e.target.value; if (value.length > 20) { e.target.value = value.substring(0, 20); } });